int temp = 0x5E; // in binary 0b1011110.
Is there such a way to check if bit 3 in temp is 1 or 0 without bit shifting and masking.
Just want to know if there is some built in function for this, or am I forced to write one myself.
In C, if you want to hide bit manipulation, you can write a macro:
#define CHECK_BIT(var,pos) ((var) & (1<<(pos)))
and use it this way to check the nth bit from the right end:
CHECK_BIT(temp, n - 1)
In C++, you can use std::bitset.
Check if bit N (starting from 0) is set:
temp & (1 << N)
There is no builtin function for this.