I need a binary search algorithm that is compatible with the C++ STL containers, something like `std::binary_search`

in the standard library's `<algorithm>`

header, but I need it to return the iterator that points at the result, not a simple boolean telling me if the element exists.

(On a side note, what the hell was the standard committee thinking when they defined the API for binary_search?!)

My main concern here is that I need the speed of a binary search, so although I can find the data with other algorithms, as mentioned below, I want to take advantage of the fact that my data is sorted to get the benefits of a binary search, not a linear search.

so far `lower_bound`

and `upper_bound`

fail if the datum is missing:

```
//lousy pseudo code
vector(1,2,3,4,6,7,8,9,0) //notice no 5
iter = lower_bound_or_upper_bound(start,end,5)
iter != 5 && iter !=end //not returning end as usual, instead it'll return 4 or 6
```

**Note:** I'm also fine using an algorithm that doesn't belong to the std namespace as long as its compatible with containers. Like, say, `boost::binary_search`

.

There is no such functions, but you can write a simple one using `std::lower_bound`

, `std::upper_bound`

or `std::equal_range`

.

A simple implementation could be

```
template<class Iter, class T>
Iter binary_find(Iter begin, Iter end, T val)
{
// Finds the lower bound in at most log(last - first) + 1 comparisons
Iter i = std::lower_bound(begin, end, val);
if (i != end && !(val < *i))
return i; // found
else
return end; // not found
}
```

Another solution would be to use a `std::set`

, which guarantees the ordering of the elements and provides a method `iterator find(T key)`

that returns an iterator to the given item. However, your requirements might not be compatible with the use of a set (for example if you need to store the same element multiple times).

You should have a look at `std::equal_range`

. It will return a pair of iterators to the range of all results.

Licensed under: CC-BY-SA with attribution

Not affiliated with: Stack Overflow