Where can I get a "useful" C++ binary search algorithm?


I need a binary search algorithm that is compatible with the C++ STL containers, something like std::binary_search in the standard library's <algorithm> header, but I need it to return the iterator that points at the result, not a simple boolean telling me if the element exists.

(On a side note, what the hell was the standard committee thinking when they defined the API for binary_search?!)

My main concern here is that I need the speed of a binary search, so although I can find the data with other algorithms, as mentioned below, I want to take advantage of the fact that my data is sorted to get the benefits of a binary search, not a linear search.

so far lower_bound and upper_bound fail if the datum is missing:

//lousy pseudo code
vector(1,2,3,4,6,7,8,9,0) //notice no 5
iter = lower_bound_or_upper_bound(start,end,5)
iter != 5 && iter !=end //not returning end as usual, instead it'll return 4 or 6

Note: I'm also fine using an algorithm that doesn't belong to the std namespace as long as its compatible with containers. Like, say, boost::binary_search.

3/24/2017 12:21:03 PM

Accepted Answer

There is no such functions, but you can write a simple one using std::lower_bound, std::upper_bound or std::equal_range.

A simple implementation could be

template<class Iter, class T>
Iter binary_find(Iter begin, Iter end, T val)
    // Finds the lower bound in at most log(last - first) + 1 comparisons
    Iter i = std::lower_bound(begin, end, val);

    if (i != end && !(val < *i))
        return i; // found
        return end; // not found

Another solution would be to use a std::set, which guarantees the ordering of the elements and provides a method iterator find(T key) that returns an iterator to the given item. However, your requirements might not be compatible with the use of a set (for example if you need to store the same element multiple times).

12/5/2013 2:37:39 PM

You should have a look at std::equal_range. It will return a pair of iterators to the range of all results.

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