C++ preprocessor __VA_ARGS__ number of arguments


Question

Simple question for which I could not find answer on the net. In variadic argument macros, how to find the number of arguments? I am okay with boost preprocessor, if it has the solution.

If it makes a difference, I am trying to convert variable number of macro arguments to boost preprocessor sequence, list, or array for further reprocessing.

1
87
5/31/2018 12:36:02 AM

Accepted Answer

This is actually compiler dependent, and not supported by any standard.

Here however you have a macro implementation that does the count:

#define PP_NARG(...) \
         PP_NARG_(__VA_ARGS__,PP_RSEQ_N())
#define PP_NARG_(...) \
         PP_ARG_N(__VA_ARGS__)
#define PP_ARG_N( \
          _1, _2, _3, _4, _5, _6, _7, _8, _9,_10, \
         _11,_12,_13,_14,_15,_16,_17,_18,_19,_20, \
         _21,_22,_23,_24,_25,_26,_27,_28,_29,_30, \
         _31,_32,_33,_34,_35,_36,_37,_38,_39,_40, \
         _41,_42,_43,_44,_45,_46,_47,_48,_49,_50, \
         _51,_52,_53,_54,_55,_56,_57,_58,_59,_60, \
         _61,_62,_63,N,...) N
#define PP_RSEQ_N() \
         63,62,61,60,                   \
         59,58,57,56,55,54,53,52,51,50, \
         49,48,47,46,45,44,43,42,41,40, \
         39,38,37,36,35,34,33,32,31,30, \
         29,28,27,26,25,24,23,22,21,20, \
         19,18,17,16,15,14,13,12,11,10, \
         9,8,7,6,5,4,3,2,1,0

/* Some test cases */


PP_NARG(A) -> 1
PP_NARG(A,B) -> 2
PP_NARG(A,B,C) -> 3
PP_NARG(A,B,C,D) -> 4
PP_NARG(A,B,C,D,E) -> 5
PP_NARG(1,2,3,4,5,6,7,8,9,0,
         1,2,3,4,5,6,7,8,9,0,
         1,2,3,4,5,6,7,8,9,0,
         1,2,3,4,5,6,7,8,9,0,
         1,2,3,4,5,6,7,8,9,0,
         1,2,3,4,5,6,7,8,9,0,
         1,2,3) -> 63
73
3/20/2015 5:44:11 PM

I usually use this macro to find a number of params:

#define NUMARGS(...)  (sizeof((int[]){__VA_ARGS__})/sizeof(int))

Full example:

#include <stdio.h>
#include <string.h>
#include <stdarg.h>

#define NUMARGS(...)  (sizeof((int[]){__VA_ARGS__})/sizeof(int))
#define SUM(...)  (sum(NUMARGS(__VA_ARGS__), __VA_ARGS__))

void sum(int numargs, ...);

int main(int argc, char *argv[]) {

    SUM(1);
    SUM(1, 2);
    SUM(1, 2, 3);
    SUM(1, 2, 3, 4);

    return 1;
}

void sum(int numargs, ...) {
    int     total = 0;
    va_list ap;

    printf("sum() called with %d params:", numargs);
    va_start(ap, numargs);
    while (numargs--)
        total += va_arg(ap, int);
    va_end(ap);

    printf(" %d\n", total);

    return;
}

It is completely valid C99 code. It has one drawback, though - you cannot invoke the macro SUM() without params, but GCC has a solution to it - see here.

So in case of GCC you need to define macros like this:

#define       NUMARGS(...)  (sizeof((int[]){0, ##__VA_ARGS__})/sizeof(int)-1)
#define       SUM(...)  sum(NUMARGS(__VA_ARGS__), ##__VA_ARGS__)

and it will work even with empty parameter list


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